Optimal. Leaf size=106 \[ \frac {a+b \tanh ^{-1}(c x)}{c^2 d^2 (c x+1)}-\frac {\log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2 d^2}+\frac {b \text {Li}_2\left (1-\frac {2}{c x+1}\right )}{2 c^2 d^2}+\frac {b}{2 c^2 d^2 (c x+1)}-\frac {b \tanh ^{-1}(c x)}{2 c^2 d^2} \]
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Rubi [A] time = 0.14, antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.444, Rules used = {5940, 5926, 627, 44, 207, 5918, 2402, 2315} \[ \frac {b \text {PolyLog}\left (2,1-\frac {2}{c x+1}\right )}{2 c^2 d^2}+\frac {a+b \tanh ^{-1}(c x)}{c^2 d^2 (c x+1)}-\frac {\log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2 d^2}+\frac {b}{2 c^2 d^2 (c x+1)}-\frac {b \tanh ^{-1}(c x)}{2 c^2 d^2} \]
Antiderivative was successfully verified.
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Rule 44
Rule 207
Rule 627
Rule 2315
Rule 2402
Rule 5918
Rule 5926
Rule 5940
Rubi steps
\begin {align*} \int \frac {x \left (a+b \tanh ^{-1}(c x)\right )}{(d+c d x)^2} \, dx &=\int \left (-\frac {a+b \tanh ^{-1}(c x)}{c d^2 (1+c x)^2}+\frac {a+b \tanh ^{-1}(c x)}{c d^2 (1+c x)}\right ) \, dx\\ &=-\frac {\int \frac {a+b \tanh ^{-1}(c x)}{(1+c x)^2} \, dx}{c d^2}+\frac {\int \frac {a+b \tanh ^{-1}(c x)}{1+c x} \, dx}{c d^2}\\ &=\frac {a+b \tanh ^{-1}(c x)}{c^2 d^2 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^2 d^2}-\frac {b \int \frac {1}{(1+c x) \left (1-c^2 x^2\right )} \, dx}{c d^2}+\frac {b \int \frac {\log \left (\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{c d^2}\\ &=\frac {a+b \tanh ^{-1}(c x)}{c^2 d^2 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^2 d^2}+\frac {b \operatorname {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+c x}\right )}{c^2 d^2}-\frac {b \int \frac {1}{(1-c x) (1+c x)^2} \, dx}{c d^2}\\ &=\frac {a+b \tanh ^{-1}(c x)}{c^2 d^2 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^2 d^2}+\frac {b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^2 d^2}-\frac {b \int \left (\frac {1}{2 (1+c x)^2}-\frac {1}{2 \left (-1+c^2 x^2\right )}\right ) \, dx}{c d^2}\\ &=\frac {b}{2 c^2 d^2 (1+c x)}+\frac {a+b \tanh ^{-1}(c x)}{c^2 d^2 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^2 d^2}+\frac {b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^2 d^2}+\frac {b \int \frac {1}{-1+c^2 x^2} \, dx}{2 c d^2}\\ &=\frac {b}{2 c^2 d^2 (1+c x)}-\frac {b \tanh ^{-1}(c x)}{2 c^2 d^2}+\frac {a+b \tanh ^{-1}(c x)}{c^2 d^2 (1+c x)}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^2 d^2}+\frac {b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^2 d^2}\\ \end {align*}
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Mathematica [A] time = 0.37, size = 99, normalized size = 0.93 \[ \frac {\frac {4 a}{c x+1}+4 a \log (c x+1)+b \left (2 \text {Li}_2\left (-e^{-2 \tanh ^{-1}(c x)}\right )-\sinh \left (2 \tanh ^{-1}(c x)\right )+\cosh \left (2 \tanh ^{-1}(c x)\right )+2 \tanh ^{-1}(c x) \left (-2 \log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )-\sinh \left (2 \tanh ^{-1}(c x)\right )+\cosh \left (2 \tanh ^{-1}(c x)\right )\right )\right )}{4 c^2 d^2} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.65, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b x \operatorname {artanh}\left (c x\right ) + a x}{c^{2} d^{2} x^{2} + 2 \, c d^{2} x + d^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \operatorname {artanh}\left (c x\right ) + a\right )} x}{{\left (c d x + d\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 192, normalized size = 1.81 \[ \frac {a}{c^{2} d^{2} \left (c x +1\right )}+\frac {a \ln \left (c x +1\right )}{c^{2} d^{2}}+\frac {b \arctanh \left (c x \right )}{c^{2} d^{2} \left (c x +1\right )}+\frac {b \arctanh \left (c x \right ) \ln \left (c x +1\right )}{c^{2} d^{2}}+\frac {b}{2 c^{2} d^{2} \left (c x +1\right )}-\frac {b \ln \left (c x +1\right )}{4 c^{2} d^{2}}+\frac {b \ln \left (c x -1\right )}{4 c^{2} d^{2}}-\frac {b \ln \left (c x +1\right )^{2}}{4 c^{2} d^{2}}+\frac {b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (c x +1\right )}{2 c^{2} d^{2}}-\frac {b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (\frac {1}{2}+\frac {c x}{2}\right )}{2 c^{2} d^{2}}-\frac {b \dilog \left (\frac {1}{2}+\frac {c x}{2}\right )}{2 c^{2} d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{8} \, {\left (8 \, c^{2} \int \frac {x^{2} \log \left (c x + 1\right )}{c^{4} d^{2} x^{3} + c^{3} d^{2} x^{2} - c^{2} d^{2} x - c d^{2}}\,{d x} - c {\left (\frac {2}{c^{4} d^{2} x + c^{3} d^{2}} + \frac {\log \left (c x + 1\right )}{c^{3} d^{2}} - \frac {\log \left (c x - 1\right )}{c^{3} d^{2}}\right )} + 4 \, c \int \frac {x \log \left (c x + 1\right )}{c^{4} d^{2} x^{3} + c^{3} d^{2} x^{2} - c^{2} d^{2} x - c d^{2}}\,{d x} - \frac {4 \, {\left ({\left (c x + 1\right )} \log \left (c x + 1\right ) + 1\right )} \log \left (-c x + 1\right )}{c^{3} d^{2} x + c^{2} d^{2}} + \frac {2}{c^{3} d^{2} x + c^{2} d^{2}} - \frac {\log \left (c x + 1\right )}{c^{2} d^{2}} + \frac {\log \left (c x - 1\right )}{c^{2} d^{2}} + 4 \, \int \frac {\log \left (c x + 1\right )}{c^{4} d^{2} x^{3} + c^{3} d^{2} x^{2} - c^{2} d^{2} x - c d^{2}}\,{d x}\right )} b + a {\left (\frac {1}{c^{3} d^{2} x + c^{2} d^{2}} + \frac {\log \left (c x + 1\right )}{c^{2} d^{2}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x\,\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )}{{\left (d+c\,d\,x\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {a x}{c^{2} x^{2} + 2 c x + 1}\, dx + \int \frac {b x \operatorname {atanh}{\left (c x \right )}}{c^{2} x^{2} + 2 c x + 1}\, dx}{d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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